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    <title>topic Re: New sim card in Archive</title>
    <link>https://helpforum.sky.com/t5/Archive/New-sim-card/m-p/3675395#M626189</link>
    <description>&lt;P&gt;You should be able to choose what sim card goes against which data package when you come to activating it.&lt;/P&gt;</description>
    <pubDate>Thu, 22 Apr 2021 12:04:37 GMT</pubDate>
    <dc:creator>caesarome</dc:creator>
    <dc:date>2021-04-22T12:04:37Z</dc:date>
    <item>
      <title>New sim card</title>
      <link>https://helpforum.sky.com/t5/Archive/New-sim-card/m-p/3675381#M626188</link>
      <description>&lt;P&gt;I have just received my new phone and 2 new sim cards.&amp;nbsp; One 10gb for my new phone and a free 100mb one.&amp;nbsp; They have both got activation codes.&amp;nbsp; When I sign in to my sky account both sim cards come up and when a click on them I need to put in the activation code for each sim.&amp;nbsp; I can't see any difference between the two sim cards, apart from they have different numbers and differenct codes.&amp;nbsp; I'm not sure which activation code to put in for my phone, or which one to put for the free extra sim.&amp;nbsp; Or are they just the same and it doesn't matter?? Thanks&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Thu, 22 Apr 2021 11:34:29 GMT</pubDate>
      <guid>https://helpforum.sky.com/t5/Archive/New-sim-card/m-p/3675381#M626188</guid>
      <dc:creator>Blencathra78</dc:creator>
      <dc:date>2021-04-22T11:34:29Z</dc:date>
    </item>
    <item>
      <title>Re: New sim card</title>
      <link>https://helpforum.sky.com/t5/Archive/New-sim-card/m-p/3675395#M626189</link>
      <description>&lt;P&gt;You should be able to choose what sim card goes against which data package when you come to activating it.&lt;/P&gt;</description>
      <pubDate>Thu, 22 Apr 2021 12:04:37 GMT</pubDate>
      <guid>https://helpforum.sky.com/t5/Archive/New-sim-card/m-p/3675395#M626189</guid>
      <dc:creator>caesarome</dc:creator>
      <dc:date>2021-04-22T12:04:37Z</dc:date>
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